Math Problems Math Answers
Tuesday, February 16, 2016
$0 \leq \lim_{n\to \infty}\frac{n!}{(2n)!} \leq \lim_{n\to \infty} \frac{n!}{(n!)^2} = \lim_{k \to \infty, k = n!}\frac{k}{k^2} = \lim_{k \to \infty}\frac{1}{k} = 0.$
No comments:
Post a Comment
Older Post
Home
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment